4x^2+28=16

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Solution for 4x^2+28=16 equation: 



4x^2+28=16

We move all terms to the left:

4x^2+28-(16)=0

We add all the numbers together, and all the variables

4x^2+12=0

a = 4; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·4·12
Δ = -192
Delta is less than zero, so there is no solution for the equation

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